4840131341 has 2 divisors, whose sum is σ = 4840131342. Its totient is φ = 4840131340.

The previous prime is 4840131287. The next prime is 4840131343. The reversal of 4840131341 is 1431310484.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4805955625 + 34175716 = 69325^2 + 5846^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4840131341 is a prime.

Together with 4840131343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4840131343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2420065670 + 2420065671.

It is an arithmetic number, because the mean of its divisors is an integer number (2420065671).

Almost surely, 2^4840131341 is an apocalyptic number.

It is an amenable number.

4840131341 is a deficient number, since it is larger than the sum of its proper divisors (1).

4840131341 is an equidigital number, since it uses as much as digits as its factorization.

4840131341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

The square root of 4840131341 is about 69571.0524643691. The cubic root of 4840131341 is about 1691.5534123322.

The spelling of 4840131341 in words is "four billion, eight hundred forty million, one hundred thirty-one thousand, three hundred forty-one".