Base | Representation |
---|---|
bin | 10110000011111001100100… |
… | …10111110001010111011111 |
3 | 20100202202020120210111220212 |
4 | 23001330302113301113133 |
5 | 22324312100134410024 |
6 | 251102200221003035 |
7 | 13134624664121663 |
oct | 1301746227612737 |
9 | 210682216714825 |
10 | 48512500700639 |
11 | 14504043a22158 |
12 | 553606a3b347b |
13 | 210b92b110171 |
14 | bda0362948a3 |
15 | 591dc4e8ba0e |
hex | 2c1f325f15df |
48512500700639 has 2 divisors, whose sum is σ = 48512500700640. Its totient is φ = 48512500700638.
The previous prime is 48512500700581. The next prime is 48512500700641. The reversal of 48512500700639 is 93600700521584.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48512500700639 - 216 = 48512500635103 is a prime.
Together with 48512500700641, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48512500700669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24256250350319 + 24256250350320.
It is an arithmetic number, because the mean of its divisors is an integer number (24256250350320).
It is a 1-persistent number, because it is pandigital, but 2⋅48512500700639 = 97025001401278 is not.
Almost surely, 248512500700639 is an apocalyptic number.
48512500700639 is a deficient number, since it is larger than the sum of its proper divisors (1).
48512500700639 is an equidigital number, since it uses as much as digits as its factorization.
48512500700639 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1814400, while the sum is 50.
The spelling of 48512500700639 in words is "forty-eight trillion, five hundred twelve billion, five hundred million, seven hundred thousand, six hundred thirty-nine".
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