Base | Representation |
---|---|
bin | 101101001100100010… |
… | …101110101110010111 |
3 | 11122021001112010101122 |
4 | 231030202232232113 |
5 | 1243341334003301 |
6 | 34143244514155 |
7 | 3335406050453 |
oct | 551442565627 |
9 | 148231463348 |
10 | 48528812951 |
11 | 19643282493 |
12 | 94a424b95b |
13 | 4765028348 |
14 | 24c51ab663 |
15 | 13e063c81b |
hex | b4c8aeb97 |
48528812951 has 2 divisors, whose sum is σ = 48528812952. Its totient is φ = 48528812950.
The previous prime is 48528812803. The next prime is 48528812953. The reversal of 48528812951 is 15921882584.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 48528812951 - 210 = 48528811927 is a prime.
Together with 48528812953, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 48528812893 and 48528812902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (48528812953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24264406475 + 24264406476.
It is an arithmetic number, because the mean of its divisors is an integer number (24264406476).
Almost surely, 248528812951 is an apocalyptic number.
48528812951 is a deficient number, since it is larger than the sum of its proper divisors (1).
48528812951 is an equidigital number, since it uses as much as digits as its factorization.
48528812951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1843200, while the sum is 53.
The spelling of 48528812951 in words is "forty-eight billion, five hundred twenty-eight million, eight hundred twelve thousand, nine hundred fifty-one".
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