Base | Representation |
---|---|
bin | 100011010110111011110… |
… | …0001110111101011111000 |
3 | 122012120111210220212210120 |
4 | 1012231313201313223320 |
5 | 1114104442011114240 |
6 | 14200250420013240 |
7 | 1011044515113630 |
oct | 106556741675370 |
9 | 18176453825716 |
10 | 4859613379320 |
11 | 1603a500765a7 |
12 | 6659aa831220 |
13 | 29334b39674b |
14 | 12b2c6a776c0 |
15 | 86622ad0ad0 |
hex | 46b77877af8 |
4859613379320 has 128 divisors (see below), whose sum is σ = 16662659005440. Its totient is φ = 1110693611520.
The previous prime is 4859613379301. The next prime is 4859613379349. The reversal of 4859613379320 is 239733169584.
It is a Harshad number since it is a multiple of its sum of digits (60).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12733680 + ... + 13109760.
It is an arithmetic number, because the mean of its divisors is an integer number (130177023480).
It is a 1-persistent number, because it is pandigital, but 2⋅4859613379320 = 9719226758640 is not.
Almost surely, 24859613379320 is an apocalyptic number.
4859613379320 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
4859613379320 is an abundant number, since it is smaller than the sum of its proper divisors (11803045626120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4859613379320 is a wasteful number, since it uses less digits than its factorization.
4859613379320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 391485 (or 391481 counting only the distinct ones).
The product of its (nonzero) digits is 29393280, while the sum is 60.
The spelling of 4859613379320 in words is "four trillion, eight hundred fifty-nine billion, six hundred thirteen million, three hundred seventy-nine thousand, three hundred twenty".
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