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49114566581 is a prime number
BaseRepresentation
bin101101101111011101…
…001100111110110101
311200202212201111022112
4231233131030332311
51301041312112311
634321331340405
73356050633133
oct555735147665
9150685644275
1049114566581
111991398a8a3
129628451705
1348294a6622
14253ccc6753
151426c9428b
hexb6f74cfb5

49114566581 has 2 divisors, whose sum is σ = 49114566582. Its totient is φ = 49114566580.

The previous prime is 49114566511. The next prime is 49114566583. The reversal of 49114566581 is 18566541194.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28496478481 + 20618088100 = 168809^2 + 143590^2 .

It is a cyclic number.

It is not a de Polignac number, because 49114566581 - 214 = 49114550197 is a prime.

It is a super-2 number, since 2×491145665812 (a number of 22 digits) contains 22 as substring.

Together with 49114566583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49114566583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24557283290 + 24557283291.

It is an arithmetic number, because the mean of its divisors is an integer number (24557283291).

Almost surely, 249114566581 is an apocalyptic number.

It is an amenable number.

49114566581 is a deficient number, since it is larger than the sum of its proper divisors (1).

49114566581 is an equidigital number, since it uses as much as digits as its factorization.

49114566581 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1036800, while the sum is 50.

The spelling of 49114566581 in words is "forty-nine billion, one hundred fourteen million, five hundred sixty-six thousand, five hundred eighty-one".