Base | Representation |
---|---|
bin | 101101101111011101… |
… | …001100111110110101 |
3 | 11200202212201111022112 |
4 | 231233131030332311 |
5 | 1301041312112311 |
6 | 34321331340405 |
7 | 3356050633133 |
oct | 555735147665 |
9 | 150685644275 |
10 | 49114566581 |
11 | 1991398a8a3 |
12 | 9628451705 |
13 | 48294a6622 |
14 | 253ccc6753 |
15 | 1426c9428b |
hex | b6f74cfb5 |
49114566581 has 2 divisors, whose sum is σ = 49114566582. Its totient is φ = 49114566580.
The previous prime is 49114566511. The next prime is 49114566583. The reversal of 49114566581 is 18566541194.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28496478481 + 20618088100 = 168809^2 + 143590^2 .
It is a cyclic number.
It is not a de Polignac number, because 49114566581 - 214 = 49114550197 is a prime.
It is a super-2 number, since 2×491145665812 (a number of 22 digits) contains 22 as substring.
Together with 49114566583, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49114566583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24557283290 + 24557283291.
It is an arithmetic number, because the mean of its divisors is an integer number (24557283291).
Almost surely, 249114566581 is an apocalyptic number.
It is an amenable number.
49114566581 is a deficient number, since it is larger than the sum of its proper divisors (1).
49114566581 is an equidigital number, since it uses as much as digits as its factorization.
49114566581 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1036800, while the sum is 50.
The spelling of 49114566581 in words is "forty-nine billion, one hundred fourteen million, five hundred sixty-six thousand, five hundred eighty-one".
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