Base | Representation |
---|---|
bin | 101101101111100100… |
… | …101000011011010000 |
3 | 11200210000101102200011 |
4 | 231233210220123100 |
5 | 1301042311422000 |
6 | 34321441204304 |
7 | 3356103323551 |
oct | 555744503320 |
9 | 150700342604 |
10 | 49116514000 |
11 | 19914a9aa34 |
12 | 9629030694 |
13 | 4829a08b48 |
14 | 253d272328 |
15 | 142702b2ba |
hex | b6f9286d0 |
49116514000 has 40 divisors (see below), whose sum is σ = 118763735688. Its totient is φ = 19646604800.
The previous prime is 49116513991. The next prime is 49116514003. The reversal of 49116514000 is 41561194.
49116514000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 218921616 + 48897592384 = 14796^2 + 221128^2 .
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49116514003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12277129 + ... + 12281128.
Almost surely, 249116514000 is an apocalyptic number.
49116514000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
49116514000 is an abundant number, since it is smaller than the sum of its proper divisors (69647221688).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
49116514000 is a wasteful number, since it uses less digits than its factorization.
49116514000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24558280 (or 24558264 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 49116514000 in words is "forty-nine billion, one hundred sixteen million, five hundred fourteen thousand".
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