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49552433837 is a prime number
BaseRepresentation
bin101110001001100011…
…100010001010101101
311201220101122110021022
4232021203202022231
51302440410340322
634433012343525
73402645511064
oct561143421255
9151811573238
1049552433837
111a019069a65
12972b014ba5
134899115a8a
1425811071db
151450437942
hexb898e22ad

49552433837 has 2 divisors, whose sum is σ = 49552433838. Its totient is φ = 49552433836.

The previous prime is 49552433767. The next prime is 49552433839. The reversal of 49552433837 is 73833425594.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49417734601 + 134699236 = 222301^2 + 11606^2 .

It is a cyclic number.

It is not a de Polignac number, because 49552433837 - 230 = 48478692013 is a prime.

Together with 49552433839, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49552433839) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24776216918 + 24776216919.

It is an arithmetic number, because the mean of its divisors is an integer number (24776216919).

Almost surely, 249552433837 is an apocalyptic number.

It is an amenable number.

49552433837 is a deficient number, since it is larger than the sum of its proper divisors (1).

49552433837 is an equidigital number, since it uses as much as digits as its factorization.

49552433837 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10886400, while the sum is 53.

The spelling of 49552433837 in words is "forty-nine billion, five hundred fifty-two million, four hundred thirty-three thousand, eight hundred thirty-seven".