495631820741 has 2 divisors, whose sum is σ = 495631820742. Its totient is φ = 495631820740.

The previous prime is 495631820693. The next prime is 495631820743. The reversal of 495631820741 is 147028136594.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 478511145025 + 17120675716 = 691745^2 + 130846^2 .

It is a cyclic number.

It is not a de Polignac number, because 495631820741 - 2¹⁰ = 495631819717 is a prime.

It is a super-3 number, since 3×495631820741³ (a number of 36 digits) contains 333 as substring.

Together with 495631820743, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 495631820741.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (495631820743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247815910370 + 247815910371.

It is an arithmetic number, because the mean of its divisors is an integer number (247815910371).

It is a 1-persistent number, because it is pandigital, but 2⋅495631820741 = 991263641482 is not.

Almost surely, 2^495631820741 is an apocalyptic number.

It is an amenable number.

495631820741 is a deficient number, since it is larger than the sum of its proper divisors (1).

495631820741 is an equidigital number, since it uses as much as digits as its factorization.

495631820741 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 495631820741 in words is "four hundred ninety-five billion, six hundred thirty-one million, eight hundred twenty thousand, seven hundred forty-one".