Base | Representation |
---|---|
bin | 1001010001111010… |
… | …01100101000001111 |
3 | 110212012200211020201 |
4 | 10220331030220033 |
5 | 40200404122242 |
6 | 2142211354331 |
7 | 234314065234 |
oct | 45075145017 |
9 | 13765624221 |
10 | 4982098447 |
11 | 21272a0337 |
12 | b705b29a7 |
13 | 615231661 |
14 | 35396178b |
15 | 1e25bc4b7 |
hex | 128f4ca0f |
4982098447 has 2 divisors, whose sum is σ = 4982098448. Its totient is φ = 4982098446.
The previous prime is 4982098441. The next prime is 4982098453. The reversal of 4982098447 is 7448902894.
It is a happy number.
4982098447 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (4982098441) and next prime (4982098453).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4982098447 is a prime.
It is a super-3 number, since 3×49820984473 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4982098441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2491049223 + 2491049224.
It is an arithmetic number, because the mean of its divisors is an integer number (2491049224).
Almost surely, 24982098447 is an apocalyptic number.
4982098447 is a deficient number, since it is larger than the sum of its proper divisors (1).
4982098447 is an equidigital number, since it uses as much as digits as its factorization.
4982098447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4644864, while the sum is 55.
The square root of 4982098447 is about 70583.9815184720. The cubic root of 4982098447 is about 1707.9327579806.
The spelling of 4982098447 in words is "four billion, nine hundred eighty-two million, ninety-eight thousand, four hundred forty-seven".
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