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5034345233501 is a prime number
BaseRepresentation
bin100100101000010011001…
…0110111111110001011101
3122211021112011201202120102
41021100212112333301131
51124440314334433001
614412425110030445
71026501524300213
oct111204626776135
918737464652512
105034345233501
111671065703861
12693834048425
132a697675553c
14135940d30cb3
158ae4ca66e6b
hex494265bfc5d

5034345233501 has 2 divisors, whose sum is σ = 5034345233502. Its totient is φ = 5034345233500.

The previous prime is 5034345233483. The next prime is 5034345233503. The reversal of 5034345233501 is 1053325434305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4790013732100 + 244331501401 = 2188610^2 + 494299^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5034345233501 is a prime.

Together with 5034345233503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5034345233503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517172616750 + 2517172616751.

It is an arithmetic number, because the mean of its divisors is an integer number (2517172616751).

Almost surely, 25034345233501 is an apocalyptic number.

It is an amenable number.

5034345233501 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034345233501 is an equidigital number, since it uses as much as digits as its factorization.

5034345233501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 38.

The spelling of 5034345233501 in words is "five trillion, thirty-four billion, three hundred forty-five million, two hundred thirty-three thousand, five hundred one".