Base | Representation |
---|---|
bin | 1001011000011000… |
… | …10110001100011111 |
3 | 110222222212200221122 |
4 | 10230030112030133 |
5 | 40303304321224 |
6 | 2151431321155 |
7 | 235543464056 |
oct | 45414261437 |
9 | 13888780848 |
10 | 5036401439 |
11 | 2154a0aa43 |
12 | b868201bb |
13 | 6235654c4 |
14 | 35ac5939d |
15 | 1e724715e |
hex | 12c31631f |
5036401439 has 2 divisors, whose sum is σ = 5036401440. Its totient is φ = 5036401438.
The previous prime is 5036401429. The next prime is 5036401441. The reversal of 5036401439 is 9341046305.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5036401439 - 212 = 5036397343 is a prime.
It is a super-2 number, since 2×50364014392 = 50730678909522541442, which contains 22 as substring.
Together with 5036401441, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5036401399 and 5036401408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5036401429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2518200719 + 2518200720.
It is an arithmetic number, because the mean of its divisors is an integer number (2518200720).
Almost surely, 25036401439 is an apocalyptic number.
5036401439 is a deficient number, since it is larger than the sum of its proper divisors (1).
5036401439 is an equidigital number, since it uses as much as digits as its factorization.
5036401439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 35.
The square root of 5036401439 is about 70967.6083787526. The cubic root of 5036401439 is about 1714.1156225344.
The spelling of 5036401439 in words is "five billion, thirty-six million, four hundred one thousand, four hundred thirty-nine".
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