Base | Representation |
---|---|
bin | 100100101011100000000… |
… | …1100110010100110011111 |
3 | 122211221021101002220020202 |
4 | 1021113000030302212133 |
5 | 1130043410112413141 |
6 | 14415523254134115 |
7 | 1030134106215323 |
oct | 111270014624637 |
9 | 18757241086222 |
10 | 5041221216671 |
11 | 1673a73a52782 |
12 | 69503295133b |
13 | 2a7501159133 |
14 | 135dd4207983 |
15 | 8b20153549b |
hex | 495c033299f |
5041221216671 has 2 divisors, whose sum is σ = 5041221216672. Its totient is φ = 5041221216670.
The previous prime is 5041221216641. The next prime is 5041221216673. The reversal of 5041221216671 is 1766121221405.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5041221216671 - 234 = 5024041347487 is a prime.
It is a super-2 number, since 2×50412212166712 (a number of 26 digits) contains 22 as substring.
Together with 5041221216673, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5041221216673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520610608335 + 2520610608336.
It is an arithmetic number, because the mean of its divisors is an integer number (2520610608336).
Almost surely, 25041221216671 is an apocalyptic number.
5041221216671 is a deficient number, since it is larger than the sum of its proper divisors (1).
5041221216671 is an equidigital number, since it uses as much as digits as its factorization.
5041221216671 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 38.
The spelling of 5041221216671 in words is "five trillion, forty-one billion, two hundred twenty-one million, two hundred sixteen thousand, six hundred seventy-one".
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