Base | Representation |
---|---|
bin | 1110101101010100010… |
… | …01000001100101010011 |
3 | 1210022102210122210102202 |
4 | 13112222021001211103 |
5 | 31234442102304011 |
6 | 1024054540033415 |
7 | 51340301200004 |
oct | 7265211014523 |
9 | 1708383583382 |
10 | 505365666131 |
11 | 18536281a917 |
12 | 81b39b3286b |
13 | 3886a989451 |
14 | 1a661aad1ab |
15 | d22bc1a23b |
hex | 75aa241953 |
505365666131 has 2 divisors, whose sum is σ = 505365666132. Its totient is φ = 505365666130.
The previous prime is 505365666109. The next prime is 505365666133. The reversal of 505365666131 is 131666563505.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-505365666131 is a prime.
It is a super-2 number, since 2×5053656661312 (a number of 24 digits) contains 22 as substring.
Together with 505365666133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (505365666133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252682833065 + 252682833066.
It is an arithmetic number, because the mean of its divisors is an integer number (252682833066).
Almost surely, 2505365666131 is an apocalyptic number.
505365666131 is a deficient number, since it is larger than the sum of its proper divisors (1).
505365666131 is an equidigital number, since it uses as much as digits as its factorization.
505365666131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458000, while the sum is 47.
The spelling of 505365666131 in words is "five hundred five billion, three hundred sixty-five million, six hundred sixty-six thousand, one hundred thirty-one".
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