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505550280503 is a prime number
BaseRepresentation
bin1110101101101010010…
…01010001011100110111
31210022220200001011202002
413112311021101130313
531240331332434003
61024125133005515
751345002324222
oct7266511213467
91708820034662
10505550280503
11185447a54384
1281b8b92389b
1338899cb7718
141a67c4085b9
15d23d035a88
hex75b5251737

505550280503 has 2 divisors, whose sum is σ = 505550280504. Its totient is φ = 505550280502.

The previous prime is 505550280467. The next prime is 505550280541. The reversal of 505550280503 is 305082055505.

It is an a-pointer prime, because the next prime (505550280541) can be obtained adding 505550280503 to its sum of digits (38).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 505550280503 - 220 = 505549231927 is a prime.

It is a super-2 number, since 2×5055502805032 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (505550280803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252775140251 + 252775140252.

It is an arithmetic number, because the mean of its divisors is an integer number (252775140252).

Almost surely, 2505550280503 is an apocalyptic number.

505550280503 is a deficient number, since it is larger than the sum of its proper divisors (1).

505550280503 is an equidigital number, since it uses as much as digits as its factorization.

505550280503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150000, while the sum is 38.

The spelling of 505550280503 in words is "five hundred five billion, five hundred fifty million, two hundred eighty thousand, five hundred three".