Base | Representation |
---|---|
bin | 1001011011100010… |
… | …00011100100100111 |
3 | 111001211112222022012 |
4 | 10231301003210213 |
5 | 40332034123303 |
6 | 2154213224435 |
7 | 236314050551 |
oct | 45561034447 |
9 | 14054488265 |
10 | 5062801703 |
11 | 2168901943 |
12 | b9363211b |
13 | 628b79b6b |
14 | 36056c4d1 |
15 | 1e970e5d8 |
hex | 12dc43927 |
5062801703 has 2 divisors, whose sum is σ = 5062801704. Its totient is φ = 5062801702.
The previous prime is 5062801691. The next prime is 5062801717. The reversal of 5062801703 is 3071082605.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5062801703 - 214 = 5062785319 is a prime.
It is a super-2 number, since 2×50628017032 = 51263922167799400418, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5062801703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5062801753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2531400851 + 2531400852.
It is an arithmetic number, because the mean of its divisors is an integer number (2531400852).
Almost surely, 25062801703 is an apocalyptic number.
5062801703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5062801703 is an equidigital number, since it uses as much as digits as its factorization.
5062801703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
The square root of 5062801703 is about 71153.3674747724. The cubic root of 5062801703 is about 1717.1054731496.
The spelling of 5062801703 in words is "five billion, sixty-two million, eight hundred one thousand, seven hundred three".
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