Base | Representation |
---|---|
bin | 101111001111000011… |
… | …110000101101010101 |
3 | 11211220122211020220222 |
4 | 233033003300231111 |
5 | 1312332414304114 |
6 | 35144425404125 |
7 | 3443565135554 |
oct | 571703605525 |
9 | 154818736828 |
10 | 50718509909 |
11 | 1a5673051a1 |
12 | 99b5639645 |
13 | 4a23890212 |
14 | 2651d25d9b |
15 | 14bc9c198e |
hex | bcf0f0b55 |
50718509909 has 2 divisors, whose sum is σ = 50718509910. Its totient is φ = 50718509908.
The previous prime is 50718509887. The next prime is 50718509911. The reversal of 50718509909 is 90990581705.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29071273009 + 21647236900 = 170503^2 + 147130^2 .
It is a cyclic number.
It is not a de Polignac number, because 50718509909 - 216 = 50718444373 is a prime.
Together with 50718509911, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50718509929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25359254954 + 25359254955.
It is an arithmetic number, because the mean of its divisors is an integer number (25359254955).
Almost surely, 250718509909 is an apocalyptic number.
It is an amenable number.
50718509909 is a deficient number, since it is larger than the sum of its proper divisors (1).
50718509909 is an equidigital number, since it uses as much as digits as its factorization.
50718509909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1020600, while the sum is 53.
The spelling of 50718509909 in words is "fifty billion, seven hundred eighteen million, five hundred nine thousand, nine hundred nine".
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