Base | Representation |
---|---|
bin | 10111001110110100000011… |
… | …10010010110110011100011 |
3 | 20200212211020022100212021201 |
4 | 23213122001302112303203 |
5 | 23144000142212330344 |
6 | 300352453403102031 |
7 | 13521610360212664 |
oct | 1347320162266343 |
9 | 220784208325251 |
10 | 51086518480099 |
11 | 1530674194a6a3 |
12 | 5890aab811917 |
13 | 2267590444b2b |
14 | c8885a40136b |
15 | 5d8d26c964d4 |
hex | 2e7681c96ce3 |
51086518480099 has 2 divisors, whose sum is σ = 51086518480100. Its totient is φ = 51086518480098.
The previous prime is 51086518480097. The next prime is 51086518480117. The reversal of 51086518480099 is 99008481568015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51086518480099 - 21 = 51086518480097 is a prime.
Together with 51086518480097, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 51086518480099.
It is not a weakly prime, because it can be changed into another prime (51086518480097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25543259240049 + 25543259240050.
It is an arithmetic number, because the mean of its divisors is an integer number (25543259240050).
Almost surely, 251086518480099 is an apocalyptic number.
51086518480099 is a deficient number, since it is larger than the sum of its proper divisors (1).
51086518480099 is an equidigital number, since it uses as much as digits as its factorization.
51086518480099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24883200, while the sum is 64.
The spelling of 51086518480099 in words is "fifty-one trillion, eighty-six billion, five hundred eighteen million, four hundred eighty thousand, ninety-nine".
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