Base | Representation |
---|---|
bin | 101111100101110011… |
… | …011111010000101111 |
3 | 11212220020220001201011 |
4 | 233211303133100233 |
5 | 1314123112320421 |
6 | 35250340530051 |
7 | 3456210566005 |
oct | 574563372057 |
9 | 155806801634 |
10 | 51100120111 |
11 | 1a74275a627 |
12 | 9aa13b0927 |
13 | 4a84963281 |
14 | 268a8a0a75 |
15 | 14e12514e1 |
hex | be5cdf42f |
51100120111 has 2 divisors, whose sum is σ = 51100120112. Its totient is φ = 51100120110.
The previous prime is 51100120109. The next prime is 51100120151. The reversal of 51100120111 is 11102100115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51100120111 - 21 = 51100120109 is a prime.
It is a super-2 number, since 2×511001201112 (a number of 22 digits) contains 22 as substring.
Together with 51100120109, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 51100120091 and 51100120100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51100120151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550060055 + 25550060056.
It is an arithmetic number, because the mean of its divisors is an integer number (25550060056).
Almost surely, 251100120111 is an apocalyptic number.
51100120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
51100120111 is an equidigital number, since it uses as much as digits as its factorization.
51100120111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10, while the sum is 13.
Adding to 51100120111 its reverse (11102100115), we get a palindrome (62202220226).
The spelling of 51100120111 in words is "fifty-one billion, one hundred million, one hundred twenty thousand, one hundred eleven".
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