51120943 has 2 divisors, whose sum is σ = 51120944. Its totient is φ = 51120942.

The previous prime is 51120941. The next prime is 51121009. The reversal of 51120943 is 34902115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51120943 - 2¹ = 51120941 is a prime.

It is a super-2 number, since 2×51120943² = 5226701626418498, which contains 22 as substring.

Together with 51120941, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51120941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25560471 + 25560472.

It is an arithmetic number, because the mean of its divisors is an integer number (25560472).

Almost surely, 2^51120943 is an apocalyptic number.

51120943 is a deficient number, since it is larger than the sum of its proper divisors (1).

51120943 is an equidigital number, since it uses as much as digits as its factorization.

51120943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

The square root of 51120943 is about 7149.8911180521. The cubic root of 51120943 is about 371.1358883986.

The spelling of 51120943 in words is "fifty-one million, one hundred twenty thousand, nine hundred forty-three".