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5112143541151 is a prime number
BaseRepresentation
bin100101001100100001101…
…1111111111001110011111
3200002201100001222021110021
41022121003133333032133
51132224132221304101
614512253013453011
71035224453063533
oct112310337771637
920081301867407
105112143541151
1116a1058834889
126a6926641167
132b10c46b55ca
1413960150bbc3
158cea2ad25a1
hex4a6437ff39f

5112143541151 has 2 divisors, whose sum is σ = 5112143541152. Its totient is φ = 5112143541150.

The previous prime is 5112143541149. The next prime is 5112143541179. The reversal of 5112143541151 is 1511453412115.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5112143541151 - 21 = 5112143541149 is a prime.

It is a super-2 number, since 2×51121435411512 (a number of 26 digits) contains 22 as substring.

Together with 5112143541149, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5112143541451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556071770575 + 2556071770576.

It is an arithmetic number, because the mean of its divisors is an integer number (2556071770576).

Almost surely, 25112143541151 is an apocalyptic number.

5112143541151 is a deficient number, since it is larger than the sum of its proper divisors (1).

5112143541151 is an equidigital number, since it uses as much as digits as its factorization.

5112143541151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12000, while the sum is 34.

Adding to 5112143541151 its reverse (1511453412115), we get a palindrome (6623596953266).

The spelling of 5112143541151 in words is "five trillion, one hundred twelve billion, one hundred forty-three million, five hundred forty-one thousand, one hundred fifty-one".