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511300000 = 25555113
BaseRepresentation
bin11110011110011…
…101000110100000
31022122002201202001
4132132131012200
52021343100000
6122422533344
715445656361
oct3636350640
91278081661
10511300000
11242685292
12123297254
1381c105a3
144bc97b68
152ed4b46a
hex1e79d1a0

511300000 has 72 divisors (see below), whose sum is σ = 1258442892. Its totient is φ = 204480000.

The previous prime is 511299961. The next prime is 511300033. The reversal of 511300000 is 3115.

It can be written as a sum of positive squares in 6 ways, for example, as 211179024 + 300120976 = 14532^2 + 17324^2 .

It is a super-2 number, since 2×5113000002 = 522855380000000000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a self number, because there is not a number n which added to its sum of digits gives 511300000.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 97444 + ... + 102556.

Almost surely, 2511300000 is an apocalyptic number.

511300000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 511300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (629221446).

511300000 is an abundant number, since it is smaller than the sum of its proper divisors (747142892).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

511300000 is an frugal number, since it uses more digits than its factorization.

511300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5148 (or 5120 counting only the distinct ones).

The product of its (nonzero) digits is 15, while the sum is 10.

The square root of 511300000 is about 22611.9437466132. The cubic root of 511300000 is about 799.6352503891.

Adding to 511300000 its reverse (3115), we get a palindrome (511303115).

The spelling of 511300000 in words is "five hundred eleven million, three hundred thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 80 100 125 160 200 250 400 500 625 800 1000 1250 2000 2500 3125 4000 5000 5113 6250 10000 10226 12500 20000 20452 25000 25565 40904 50000 51130 81808 100000 102260 127825 163616 204520 255650 409040 511300 639125 818080 1022600 1278250 2045200 2556500 3195625 4090400 5113000 6391250 10226000 12782500 15978125 20452000 25565000 31956250 51130000 63912500 102260000 127825000 255650000 511300000