Base | Representation |
---|---|
bin | 100101001101000010110… |
… | …1001011000100001110100 |
3 | 200002211012102011212212110 |
4 | 1022122011221120201310 |
5 | 1132233420321102330 |
6 | 14512555055451020 |
7 | 1035264116634213 |
oct | 112320551304164 |
9 | 20084172155773 |
10 | 5113253300340 |
11 | 16a1578205339 |
12 | 6a6b96226a70 |
13 | 2b12405a2353 |
14 | 1396a8a6b07a |
15 | 8d01a244db0 |
hex | 4a685a58874 |
5113253300340 has 96 divisors (see below), whose sum is σ = 14381208301824. Its totient is φ = 1357440578560.
The previous prime is 5113253300329. The next prime is 5113253300357. The reversal of 5113253300340 is 430033523115.
It is a super-2 number, since 2×51132533003402 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 5113253300298 and 5113253300307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14700112 + ... + 15043928.
It is an arithmetic number, because the mean of its divisors is an integer number (149804253144).
Almost surely, 25113253300340 is an apocalyptic number.
It is an amenable number.
5113253300340 is an abundant number, since it is smaller than the sum of its proper divisors (9267955001484).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5113253300340 is a wasteful number, since it uses less digits than its factorization.
5113253300340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 344937 (or 344935 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 30.
Adding to 5113253300340 its reverse (430033523115), we get a palindrome (5543286823455).
The spelling of 5113253300340 in words is "five trillion, one hundred thirteen billion, two hundred fifty-three million, three hundred thousand, three hundred forty".
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