Base | Representation |
---|---|
bin | 100101001101101000111… |
… | …1100101100101011000000 |
3 | 200002221111121222022101011 |
4 | 1022123101330230223000 |
5 | 1132244031024311000 |
6 | 14513330105250304 |
7 | 1035340622604406 |
oct | 112332174545300 |
9 | 20087447868334 |
10 | 5114533432000 |
11 | 16a2074872193 |
12 | 6a7292a93994 |
13 | 2b13b5871ac5 |
14 | 13978aa99476 |
15 | 8d09280d2ba |
hex | 4a6d1f2cac0 |
5114533432000 has 56 divisors (see below), whose sum is σ = 12666142064160. Its totient is φ = 2045813369600.
The previous prime is 5114533431947. The next prime is 5114533432013. The reversal of 5114533432000 is 2343354115.
It is a super-3 number, since 3×51145334320003 (a number of 39 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 319650340 + ... + 319666339.
Almost surely, 25114533432000 is an apocalyptic number.
5114533432000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5114533432000 is an abundant number, since it is smaller than the sum of its proper divisors (7551608632160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5114533432000 is an equidigital number, since it uses as much as digits as its factorization.
5114533432000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 639316706 (or 639316686 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5114533432000 its reverse (2343354115), we get a palindrome (5116876786115).
The spelling of 5114533432000 in words is "five trillion, one hundred fourteen billion, five hundred thirty-three million, four hundred thirty-two thousand".
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