Base | Representation |
---|---|
bin | 101111101000110110… |
… | …110101101011010000 |
3 | 11220000211020210110201 |
4 | 233220312311223100 |
5 | 1314224220030000 |
6 | 35255410304544 |
7 | 3460402062661 |
oct | 575066655320 |
9 | 156024223421 |
10 | 51151330000 |
11 | 1a769657351 |
12 | 9ab6588154 |
13 | 4a92453294 |
14 | 26935d1368 |
15 | 14e59b996a |
hex | be8db5ad0 |
51151330000 has 50 divisors (see below), whose sum is σ = 123842509274. Its totient is φ = 20460528000.
The previous prime is 51151329989. The next prime is 51151330049. The reversal of 51151330000 is 3315115.
It can be written as a sum of positive squares in 5 ways, for example, as 19018616464 + 32132713536 = 137908^2 + 179256^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a self number, because there is not a number n which added to its sum of digits gives 51151330000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 2547567 + ... + 2567566.
Almost surely, 251151330000 is an apocalyptic number.
51151330000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51151330000 is an abundant number, since it is smaller than the sum of its proper divisors (72691179274).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51151330000 is an equidigital number, since it uses as much as digits as its factorization.
51151330000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5115161 (or 5115140 counting only the distinct ones).
The product of its (nonzero) digits is 225, while the sum is 19.
Adding to 51151330000 its reverse (3315115), we get a palindrome (51154645115).
The spelling of 51151330000 in words is "fifty-one billion, one hundred fifty-one million, three hundred thirty thousand".
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