Base | Representation |
---|---|
bin | 10111010000111111011101… |
… | …11111010001001001000110 |
3 | 20201010222102111100022101021 |
4 | 23220133232333101021012 |
5 | 23201211433421302400 |
6 | 300451112344221354 |
7 | 13530200214311116 |
oct | 1350375677211106 |
9 | 221128374308337 |
10 | 51161365025350 |
11 | 1533545a867968 |
12 | 58a34b976a85a |
13 | 227165a9ac828 |
14 | c8c31a971046 |
15 | 5dac57aea71a |
hex | 2e87eefd1246 |
51161365025350 has 36 divisors (see below), whose sum is σ = 97537727349972. Its totient is φ = 19965410708800.
The previous prime is 51161365025341. The next prime is 51161365025387. The reversal of 51161365025350 is 5352056316115.
It is a super-2 number, since 2×511613650253502 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51161365025297 and 51161365025306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 304266724 + ... + 304434823.
It is an arithmetic number, because the mean of its divisors is an integer number (2709381315277).
Almost surely, 251161365025350 is an apocalyptic number.
51161365025350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
51161365025350 is a deficient number, since it is larger than the sum of its proper divisors (46376362324622).
51161365025350 is a wasteful number, since it uses less digits than its factorization.
51161365025350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 608701641 (or 608701595 counting only the distinct ones).
The product of its (nonzero) digits is 405000, while the sum is 43.
The spelling of 51161365025350 in words is "fifty-one trillion, one hundred sixty-one billion, three hundred sixty-five million, twenty-five thousand, three hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •