Base | Representation |
---|---|
bin | 100101010000101101000… |
… | …1101100001110010100111 |
3 | 200010120111021102211201021 |
4 | 1022201122031201302213 |
5 | 1132401020303400201 |
6 | 14520335120512011 |
7 | 1035662664063232 |
oct | 112413215416247 |
9 | 20116437384637 |
10 | 5121114512551 |
11 | 16a49416a9434 |
12 | 6a860aa7b607 |
13 | 2b1bc4140acb |
14 | 139c12b28419 |
15 | 8d32a477ea1 |
hex | 4a85a361ca7 |
5121114512551 has 2 divisors, whose sum is σ = 5121114512552. Its totient is φ = 5121114512550.
The previous prime is 5121114512539. The next prime is 5121114512561. The reversal of 5121114512551 is 1552154111215.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5121114512551 - 229 = 5120577641639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5121114512531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560557256275 + 2560557256276.
It is an arithmetic number, because the mean of its divisors is an integer number (2560557256276).
Almost surely, 25121114512551 is an apocalyptic number.
5121114512551 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121114512551 is an equidigital number, since it uses as much as digits as its factorization.
5121114512551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10000, while the sum is 34.
Adding to 5121114512551 its reverse (1552154111215), we get a palindrome (6673268623766).
The spelling of 5121114512551 in words is "five trillion, one hundred twenty-one billion, one hundred fourteen million, five hundred twelve thousand, five hundred fifty-one".
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