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512132205111550 = 25210242644102231
BaseRepresentation
bin111010001110010000001001…
…0001010011110100011111110
32111011022100201220220021012221
41310130200102022132203332
51014111233224002032200
65013114142002115554
7212605221315043252
oct16434402212364376
92434270656807187
10512132205111550
111391aa059587741
124953279b34bbba
1318c9bb23a5921a
14906748c312262
153e31b0205d91a
hex1d1c81229e8fe

512132205111550 has 12 divisors (see below), whose sum is σ = 952565901507576. Its totient is φ = 204852882044600.

The previous prime is 512132205111529. The next prime is 512132205111613. The reversal of 512132205111550 is 55111502231215.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5121322051066 + ... + 5121322051165.

It is an arithmetic number, because the mean of its divisors is an integer number (79380491792298).

Almost surely, 2512132205111550 is an apocalyptic number.

512132205111550 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

512132205111550 is a deficient number, since it is larger than the sum of its proper divisors (440433696396026).

512132205111550 is a wasteful number, since it uses less digits than its factorization.

512132205111550 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10242644102243 (or 10242644102238 counting only the distinct ones).

The product of its (nonzero) digits is 15000, while the sum is 34.

Adding to 512132205111550 its reverse (55111502231215), we get a palindrome (567243707342765).

The spelling of 512132205111550 in words is "five hundred twelve trillion, one hundred thirty-two billion, two hundred five million, one hundred eleven thousand, five hundred fifty".

Divisors: 1 2 5 10 25 50 10242644102231 20485288204462 51213220511155 102426441022310 256066102555775 512132205111550