Base | Representation |
---|---|
bin | 1001100011011110… |
… | …00101100100000101 |
3 | 111020110212020100202 |
4 | 10301233011210011 |
5 | 41001111110222 |
6 | 2204552420245 |
7 | 241053063506 |
oct | 46157054405 |
9 | 14213766322 |
10 | 5129394437 |
11 | 21a2455a62 |
12 | bb19a7685 |
13 | 6398c484b |
14 | 369344bad |
15 | 2004b5892 |
hex | 131bc5905 |
5129394437 has 2 divisors, whose sum is σ = 5129394438. Its totient is φ = 5129394436.
The previous prime is 5129394379. The next prime is 5129394443. The reversal of 5129394437 is 7344939215.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3609486241 + 1519908196 = 60079^2 + 38986^2 .
It is a cyclic number.
It is not a de Polignac number, because 5129394437 - 230 = 4055652613 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5129394391 and 5129394400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5129394637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2564697218 + 2564697219.
It is an arithmetic number, because the mean of its divisors is an integer number (2564697219).
Almost surely, 25129394437 is an apocalyptic number.
It is an amenable number.
5129394437 is a deficient number, since it is larger than the sum of its proper divisors (1).
5129394437 is an equidigital number, since it uses as much as digits as its factorization.
5129394437 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 816480, while the sum is 47.
The square root of 5129394437 is about 71619.7908192980. The cubic root of 5129394437 is about 1724.6012590372.
The spelling of 5129394437 in words is "five billion, one hundred twenty-nine million, three hundred ninety-four thousand, four hundred thirty-seven".
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