Base | Representation |
---|---|
bin | 111010010100100111010111… |
… | …0111010111101000011101111 |
3 | 2111021101221222220120120002022 |
4 | 1310221032232322331003233 |
5 | 1014220100222114114114 |
6 | 5015024010342220355 |
7 | 213025340411055311 |
oct | 16451165672750357 |
9 | 2437357886516068 |
10 | 513006713426159 |
11 | 139506a1a742a47 |
12 | 4965417a4246bb |
13 | 19033430178404 |
14 | 909792bd217b1 |
15 | 3e4973664348e |
hex | 1d293aeebd0ef |
513006713426159 has 2 divisors, whose sum is σ = 513006713426160. Its totient is φ = 513006713426158.
The previous prime is 513006713426153. The next prime is 513006713426189. The reversal of 513006713426159 is 951624317600315.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513006713426159 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 513006713426159.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513006713426153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256503356713079 + 256503356713080.
It is an arithmetic number, because the mean of its divisors is an integer number (256503356713080).
Almost surely, 2513006713426159 is an apocalyptic number.
513006713426159 is a deficient number, since it is larger than the sum of its proper divisors (1).
513006713426159 is an equidigital number, since it uses as much as digits as its factorization.
513006713426159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4082400, while the sum is 53.
The spelling of 513006713426159 in words is "five hundred thirteen trillion, six billion, seven hundred thirteen million, four hundred twenty-six thousand, one hundred fifty-nine".
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