Base | Representation |
---|---|
bin | 1110111101011010001… |
… | …01100110010011011001 |
3 | 1211010201220011011102221 |
4 | 13132231011212103121 |
5 | 31410140242043301 |
6 | 1032044115424041 |
7 | 52064344463011 |
oct | 7365505462331 |
9 | 1733656134387 |
10 | 514005034201 |
11 | 188a96494a2a |
12 | 8374b2b5021 |
13 | 39616800169 |
14 | 1ac4124ac41 |
15 | d58540cda1 |
hex | 77ad1664d9 |
514005034201 has 2 divisors, whose sum is σ = 514005034202. Its totient is φ = 514005034200.
The previous prime is 514005034183. The next prime is 514005034219. The reversal of 514005034201 is 102430500415.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (514005034183) and next prime (514005034219).
It can be written as a sum of positive squares in only one way, i.e., 511545370176 + 2459664025 = 715224^2 + 49595^2 .
It is a cyclic number.
It is not a de Polignac number, because 514005034201 - 237 = 376566080729 is a prime.
It is not a weakly prime, because it can be changed into another prime (514005034801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257002517100 + 257002517101.
It is an arithmetic number, because the mean of its divisors is an integer number (257002517101).
Almost surely, 2514005034201 is an apocalyptic number.
It is an amenable number.
514005034201 is a deficient number, since it is larger than the sum of its proper divisors (1).
514005034201 is an equidigital number, since it uses as much as digits as its factorization.
514005034201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 514005034201 its reverse (102430500415), we get a palindrome (616435534616).
The spelling of 514005034201 in words is "five hundred fourteen billion, five million, thirty-four thousand, two hundred one".
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