Base | Representation |
---|---|
bin | 1110111101011011000… |
… | …10001111000101111111 |
3 | 1211010202102021120021001 |
4 | 13132231202033011333 |
5 | 31410144202310221 |
6 | 1032044544351131 |
7 | 52064465340433 |
oct | 7365542170577 |
9 | 1733672246231 |
10 | 514012541311 |
11 | 188a9a752155 |
12 | 837519154a7 |
13 | 3961822b139 |
14 | 1ac422429c3 |
15 | d585de2391 |
hex | 77ad88f17f |
514012541311 has 2 divisors, whose sum is σ = 514012541312. Its totient is φ = 514012541310.
The previous prime is 514012541309. The next prime is 514012541321. The reversal of 514012541311 is 113145210415.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 514012541311 - 21 = 514012541309 is a prime.
Together with 514012541309, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 514012541311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (514012541321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257006270655 + 257006270656.
It is an arithmetic number, because the mean of its divisors is an integer number (257006270656).
Almost surely, 2514012541311 is an apocalyptic number.
514012541311 is a deficient number, since it is larger than the sum of its proper divisors (1).
514012541311 is an equidigital number, since it uses as much as digits as its factorization.
514012541311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 514012541311 its reverse (113145210415), we get a palindrome (627157751726).
The spelling of 514012541311 in words is "five hundred fourteen billion, twelve million, five hundred forty-one thousand, three hundred eleven".
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