514403413 has 2 divisors, whose sum is σ = 514403414. Its totient is φ = 514403412.

The previous prime is 514403411. The next prime is 514403431. The reversal of 514403413 is 314304415.

Together with next prime (514403431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 404090404 + 110313009 = 20102^2 + 10503^2 .

It is a cyclic number.

It is not a de Polignac number, because 514403413 - 2¹ = 514403411 is a prime.

It is a super-2 number, since 2×514403413² = 529221742612097138, which contains 22 as substring.

Together with 514403411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514403411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257201706 + 257201707.

It is an arithmetic number, because the mean of its divisors is an integer number (257201707).

Almost surely, 2^514403413 is an apocalyptic number.

It is an amenable number.

514403413 is a deficient number, since it is larger than the sum of its proper divisors (1).

514403413 is an equidigital number, since it uses as much as digits as its factorization.

514403413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 514403413 is about 22680.4632448281. The cubic root of 514403413 is about 801.2498240123.

Adding to 514403413 its reverse (314304415), we get a palindrome (828707828).

The spelling of 514403413 in words is "five hundred fourteen million, four hundred three thousand, four hundred thirteen".