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514405234141 is a prime number
BaseRepresentation
bin1110111110001001111…
…00001111010111011101
31211011202210012102112221
413133010330033113131
531412000214443031
61032151533225341
752110304226461
oct7370474172735
91734683172487
10514405234141
11189181387087
1283841332251
133967b6b1766
141ac7c4644a1
15d5aa610a11
hex77c4f0f5dd

514405234141 has 2 divisors, whose sum is σ = 514405234142. Its totient is φ = 514405234140.

The previous prime is 514405234097. The next prime is 514405234159. The reversal of 514405234141 is 141432504415.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 317668631641 + 196736602500 = 563621^2 + 443550^2 .

It is a cyclic number.

It is not a de Polignac number, because 514405234141 - 211 = 514405232093 is a prime.

It is a super-2 number, since 2×5144052341412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 514405234097 and 514405234106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514405234741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257202617070 + 257202617071.

It is an arithmetic number, because the mean of its divisors is an integer number (257202617071).

Almost surely, 2514405234141 is an apocalyptic number.

It is an amenable number.

514405234141 is a deficient number, since it is larger than the sum of its proper divisors (1).

514405234141 is an equidigital number, since it uses as much as digits as its factorization.

514405234141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38400, while the sum is 34.

Adding to 514405234141 its reverse (141432504415), we get a palindrome (655837738556).

The spelling of 514405234141 in words is "five hundred fourteen billion, four hundred five million, two hundred thirty-four thousand, one hundred forty-one".