Base | Representation |
---|---|
bin | 110000000101100100… |
… | …101110100011010101 |
3 | 11221021101211100011002 |
4 | 300011210232203111 |
5 | 1321221034341433 |
6 | 35415300553045 |
7 | 3505342201622 |
oct | 600544564325 |
9 | 157241740132 |
10 | 51633121493 |
11 | 1a996607438 |
12 | a00b9b2785 |
13 | 4b3b2014c5 |
14 | 26db5a7349 |
15 | 1522e379e8 |
hex | c0592e8d5 |
51633121493 has 2 divisors, whose sum is σ = 51633121494. Its totient is φ = 51633121492.
The previous prime is 51633121451. The next prime is 51633121499. The reversal of 51633121493 is 39412133615.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51618931204 + 14190289 = 227198^2 + 3767^2 .
It is a cyclic number.
It is not a de Polignac number, because 51633121493 - 28 = 51633121237 is a prime.
It is a super-3 number, since 3×516331214933 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51633121499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25816560746 + 25816560747.
It is an arithmetic number, because the mean of its divisors is an integer number (25816560747).
Almost surely, 251633121493 is an apocalyptic number.
It is an amenable number.
51633121493 is a deficient number, since it is larger than the sum of its proper divisors (1).
51633121493 is an equidigital number, since it uses as much as digits as its factorization.
51633121493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 58320, while the sum is 38.
It can be divided in two parts, 516331 and 21493, that added together give a 5-th power (537824 = 145).
The spelling of 51633121493 in words is "fifty-one billion, six hundred thirty-three million, one hundred twenty-one thousand, four hundred ninety-three".
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