Base | Representation |
---|---|
bin | 1001100111100101… |
… | …11011101011110101 |
3 | 111022212220012020222 |
4 | 10303302323223311 |
5 | 41033433110411 |
6 | 2212225304125 |
7 | 241652624111 |
oct | 46362735365 |
9 | 14285805228 |
10 | 5163956981 |
11 | 220aa12347 |
12 | 1001495045 |
13 | 643b06461 |
14 | 36db80741 |
15 | 2035414db |
hex | 133cbbaf5 |
5163956981 has 2 divisors, whose sum is σ = 5163956982. Its totient is φ = 5163956980.
The previous prime is 5163956957. The next prime is 5163956983. The reversal of 5163956981 is 1896593615.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5145766756 + 18190225 = 71734^2 + 4265^2 .
It is a cyclic number.
It is not a de Polignac number, because 5163956981 - 226 = 5096848117 is a prime.
It is a super-2 number, since 2×51639569812 = 53332903403237268722, which contains 22 as substring.
Together with 5163956983, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5163956983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2581978490 + 2581978491.
It is an arithmetic number, because the mean of its divisors is an integer number (2581978491).
Almost surely, 25163956981 is an apocalyptic number.
It is an amenable number.
5163956981 is a deficient number, since it is larger than the sum of its proper divisors (1).
5163956981 is an equidigital number, since it uses as much as digits as its factorization.
5163956981 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1749600, while the sum is 53.
The square root of 5163956981 is about 71860.6775712559. The cubic root of 5163956981 is about 1728.4661224541.
The spelling of 5163956981 in words is "five billion, one hundred sixty-three million, nine hundred fifty-six thousand, nine hundred eighty-one".
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