Base | Representation |
---|---|
bin | 1001101000111001… |
… | …11100111001001101 |
3 | 111100122121210222221 |
4 | 10310130330321031 |
5 | 41044243100411 |
6 | 2213301335341 |
7 | 242145351604 |
oct | 46434747115 |
9 | 14318553887 |
10 | 5174971981 |
11 | 2216156053 |
12 | 1005107551 |
13 | 646191cca |
14 | 37140aa3b |
15 | 2044ba071 |
hex | 13473ce4d |
5174971981 has 2 divisors, whose sum is σ = 5174971982. Its totient is φ = 5174971980.
The previous prime is 5174971979. The next prime is 5174972029. The reversal of 5174971981 is 1891794715.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4972365225 + 202606756 = 70515^2 + 14234^2 .
It is a cyclic number.
It is not a de Polignac number, because 5174971981 - 21 = 5174971979 is a prime.
It is a super-2 number, since 2×51749719812 = 53560670008270128722, which contains 22 as substring.
Together with 5174971979, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5174971931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2587485990 + 2587485991.
It is an arithmetic number, because the mean of its divisors is an integer number (2587485991).
Almost surely, 25174971981 is an apocalyptic number.
It is an amenable number.
5174971981 is a deficient number, since it is larger than the sum of its proper divisors (1).
5174971981 is an equidigital number, since it uses as much as digits as its factorization.
5174971981 is an evil number, because the sum of its binary digits is even.
The product of its digits is 635040, while the sum is 52.
The square root of 5174971981 is about 71937.2781039149. The cubic root of 5174971981 is about 1729.6942202944.
The spelling of 5174971981 in words is "five billion, one hundred seventy-four million, nine hundred seventy-one thousand, nine hundred eighty-one".
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