Base | Representation |
---|---|
bin | 100101101110000100101… |
… | …0111010101001010001111 |
3 | 200100121021121020112020201 |
4 | 1023130021113111022033 |
5 | 1134414201223342244 |
6 | 15005325225354331 |
7 | 1043354610226606 |
oct | 113341127251217 |
9 | 20317247215221 |
10 | 5184182637199 |
11 | 1719665a469a5 |
12 | 6b88903389a7 |
13 | 2b7b35415567 |
14 | 13ccb6c78a3d |
15 | 8ecbc229ad4 |
hex | 4b7095d528f |
5184182637199 has 2 divisors, whose sum is σ = 5184182637200. Its totient is φ = 5184182637198.
The previous prime is 5184182637197. The next prime is 5184182637203. The reversal of 5184182637199 is 9917362814815.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5184182637199 - 21 = 5184182637197 is a prime.
Together with 5184182637197, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 5184182637199.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5184182637197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2592091318599 + 2592091318600.
It is an arithmetic number, because the mean of its divisors is an integer number (2592091318600).
Almost surely, 25184182637199 is an apocalyptic number.
5184182637199 is a deficient number, since it is larger than the sum of its proper divisors (1).
5184182637199 is an equidigital number, since it uses as much as digits as its factorization.
5184182637199 is an evil number, because the sum of its binary digits is even.
The product of its digits is 26127360, while the sum is 64.
The spelling of 5184182637199 in words is "five trillion, one hundred eighty-four billion, one hundred eighty-two million, six hundred thirty-seven thousand, one hundred ninety-nine".
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