Base | Representation |
---|---|
bin | 100101111010010000000… |
… | …0110110111010011101111 |
3 | 200110002210010122102101221 |
4 | 1023310200012313103233 |
5 | 1140331231001002432 |
6 | 15025332220044211 |
7 | 1045301635160116 |
oct | 113644006672357 |
9 | 20402703572357 |
10 | 5210334000367 |
11 | 172976578a131 |
12 | 70196a393667 |
13 | 2ba442344452 |
14 | 1402780d0c7d |
15 | 907ed02bb97 |
hex | 4bd201b74ef |
5210334000367 has 2 divisors, whose sum is σ = 5210334000368. Its totient is φ = 5210334000366.
The previous prime is 5210334000307. The next prime is 5210334000427. The reversal of 5210334000367 is 7630004330125.
It is a balanced prime because it is at equal distance from previous prime (5210334000307) and next prime (5210334000427).
It is a cyclic number.
It is not a de Polignac number, because 5210334000367 - 215 = 5210333967599 is a prime.
It is a super-2 number, since 2×52103340003672 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5210334000307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2605167000183 + 2605167000184.
It is an arithmetic number, because the mean of its divisors is an integer number (2605167000184).
Almost surely, 25210334000367 is an apocalyptic number.
5210334000367 is a deficient number, since it is larger than the sum of its proper divisors (1).
5210334000367 is an equidigital number, since it uses as much as digits as its factorization.
5210334000367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45360, while the sum is 34.
The spelling of 5210334000367 in words is "five trillion, two hundred ten billion, three hundred thirty-four million, three hundred sixty-seven", and thus it is an aban number.
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