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5215442015981 is a prime number
BaseRepresentation
bin100101111100101000010…
…0100011001011011101101
3200110120222010021111112102
41023321100210121123231
51140422211124002411
615031535130344445
71045542341452661
oct113712044313355
920416863244472
105215442015981
11173094706293a
12702954b8b125
132baa776920b2
1414060066c8a1
15909eb6bcd3b
hex4be509196ed

5215442015981 has 2 divisors, whose sum is σ = 5215442015982. Its totient is φ = 5215442015980.

The previous prime is 5215442015897. The next prime is 5215442016007. The reversal of 5215442015981 is 1895102445125.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4902278663881 + 313163352100 = 2214109^2 + 559610^2 .

It is a cyclic number.

It is not a de Polignac number, because 5215442015981 - 210 = 5215442014957 is a prime.

It is a super-3 number, since 3×52154420159813 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5215442015681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2607721007990 + 2607721007991.

It is an arithmetic number, because the mean of its divisors is an integer number (2607721007991).

Almost surely, 25215442015981 is an apocalyptic number.

It is an amenable number.

5215442015981 is a deficient number, since it is larger than the sum of its proper divisors (1).

5215442015981 is an equidigital number, since it uses as much as digits as its factorization.

5215442015981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576000, while the sum is 47.

The spelling of 5215442015981 in words is "five trillion, two hundred fifteen billion, four hundred forty-two million, fifteen thousand, nine hundred eighty-one".