Base | Representation |
---|---|
bin | 100101111100101011100… |
… | …0001110110101100010100 |
3 | 200110121020200020001020111 |
4 | 1023321113001312230110 |
5 | 1140422421400320200 |
6 | 15031554001412404 |
7 | 1045545125641111 |
oct | 113712701665424 |
9 | 20417220201214 |
10 | 5215550401300 |
11 | 17309a2261388 |
12 | 70298533a104 |
13 | 2baa93c80515 |
14 | 140610c03908 |
15 | 90a05e7c0ba |
hex | 4be57076b14 |
5215550401300 has 36 divisors (see below), whose sum is σ = 11913415131520. Its totient is φ = 1976419098720.
The previous prime is 5215550401279. The next prime is 5215550401301. The reversal of 5215550401300 is 31040555125.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5215550401301) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1372511364 + ... + 1372515163.
Almost surely, 25215550401300 is an apocalyptic number.
5215550401300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5215550401300 is an abundant number, since it is smaller than the sum of its proper divisors (6697864730220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5215550401300 is a wasteful number, since it uses less digits than its factorization.
5215550401300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2745026560 (or 2745026553 counting only the distinct ones).
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 5215550401300 its reverse (31040555125), we get a palindrome (5246590956425).
The spelling of 5215550401300 in words is "five trillion, two hundred fifteen billion, five hundred fifty million, four hundred one thousand, three hundred".
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