Base | Representation |
---|---|
bin | 10111110101010111001001… |
… | …00100001010100000100111 |
3 | 20212120110000111020120211111 |
4 | 23322223210210022200213 |
5 | 23332200240030200041 |
6 | 303245143124045451 |
7 | 14016400034224606 |
oct | 1372534444124047 |
9 | 225513014216744 |
10 | 52411025631271 |
11 | 1577743368622a |
12 | 5a65736533887 |
13 | 2332452925648 |
14 | cd29c86bda3d |
15 | 60d4e7489981 |
hex | 2faae490a827 |
52411025631271 has 2 divisors, whose sum is σ = 52411025631272. Its totient is φ = 52411025631270.
The previous prime is 52411025631253. The next prime is 52411025631311. The reversal of 52411025631271 is 17213652011425.
It is a happy number.
It is an a-pointer prime, because the next prime (52411025631311) can be obtained adding 52411025631271 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52411025631271 - 213 = 52411025623079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52411025631241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26205512815635 + 26205512815636.
It is an arithmetic number, because the mean of its divisors is an integer number (26205512815636).
Almost surely, 252411025631271 is an apocalyptic number.
52411025631271 is a deficient number, since it is larger than the sum of its proper divisors (1).
52411025631271 is an equidigital number, since it uses as much as digits as its factorization.
52411025631271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 40.
Adding to 52411025631271 its reverse (17213652011425), we get a palindrome (69624677642696).
The spelling of 52411025631271 in words is "fifty-two trillion, four hundred eleven billion, twenty-five million, six hundred thirty-one thousand, two hundred seventy-one".
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