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52455003914893 is a prime number
BaseRepresentation
bin10111110110101001000011…
…11000000000001010001101
320212201122112102010212111211
423323110201320000022031
523333410322000234033
6303321255055214421
714022514616404126
oct1373244170001215
9225648472125454
1052455003914893
1115794051235678
125a7216a817411
132336640c64b88
14cd4b9b38b04d
1560e71d3572cd
hex2fb521e0028d

52455003914893 has 2 divisors, whose sum is σ = 52455003914894. Its totient is φ = 52455003914892.

The previous prime is 52455003914891. The next prime is 52455003914899. The reversal of 52455003914893 is 39841930055425.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32768274512164 + 19686729402729 = 5724358^2 + 4436973^2 .

It is a cyclic number.

It is not a de Polignac number, because 52455003914893 - 21 = 52455003914891 is a prime.

It is a super-2 number, since 2×524550039148932 (a number of 28 digits) contains 22 as substring.

Together with 52455003914891, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52455003914891) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26227501957446 + 26227501957447.

It is an arithmetic number, because the mean of its divisors is an integer number (26227501957447).

Almost surely, 252455003914893 is an apocalyptic number.

It is an amenable number.

52455003914893 is a deficient number, since it is larger than the sum of its proper divisors (1).

52455003914893 is an equidigital number, since it uses as much as digits as its factorization.

52455003914893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328000, while the sum is 58.

The spelling of 52455003914893 in words is "fifty-two trillion, four hundred fifty-five billion, three million, nine hundred fourteen thousand, eight hundred ninety-three".