Base | Representation |
---|---|
bin | 100110011010010100001… |
… | …0000110111011001110111 |
3 | 200200200111211221201011211 |
4 | 1030310220100313121313 |
5 | 1142443240210113123 |
6 | 15121120533542251 |
7 | 1053260154204004 |
oct | 114645020673167 |
9 | 20620454851154 |
10 | 5279190316663 |
11 | 175598a33a75a |
12 | 7131861a4987 |
13 | 2c3a96854983 |
14 | 14372ac768ab |
15 | 924cd02840d |
hex | 4cd28437677 |
5279190316663 has 2 divisors, whose sum is σ = 5279190316664. Its totient is φ = 5279190316662.
The previous prime is 5279190316661. The next prime is 5279190316711. The reversal of 5279190316663 is 3666130919725.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5279190316663 - 21 = 5279190316661 is a prime.
Together with 5279190316661, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 5279190316598 and 5279190316607.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5279190316661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2639595158331 + 2639595158332.
It is an arithmetic number, because the mean of its divisors is an integer number (2639595158332).
Almost surely, 25279190316663 is an apocalyptic number.
5279190316663 is a deficient number, since it is larger than the sum of its proper divisors (1).
5279190316663 is an equidigital number, since it uses as much as digits as its factorization.
5279190316663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11022480, while the sum is 58.
The spelling of 5279190316663 in words is "five trillion, two hundred seventy-nine billion, one hundred ninety million, three hundred sixteen thousand, six hundred sixty-three".
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