Base | Representation |
---|---|
bin | 11000000110100000100111… |
… | …11000100011000010101100 |
3 | 20221122202212011020221021221 |
4 | 30003100103320203002230 |
5 | 23421323432341221330 |
6 | 304415545231033124 |
7 | 14110066052016205 |
oct | 1403202370430254 |
9 | 227582764227257 |
10 | 53000230023340 |
11 | 159842a91537a6 |
12 | 5b3b97196b7a4 |
13 | 2375b91abc962 |
14 | d13320c9a5ac |
15 | 61d9ce68db7a |
hex | 303413e230ac |
53000230023340 has 12 divisors (see below), whose sum is σ = 111300483049056. Its totient is φ = 21200092009328.
The previous prime is 53000230023313. The next prime is 53000230023341. The reversal of 53000230023340 is 4332003200035.
It is not an unprimeable number, because it can be changed into a prime (53000230023341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1325005750564 + ... + 1325005750603.
It is an arithmetic number, because the mean of its divisors is an integer number (9275040254088).
Almost surely, 253000230023340 is an apocalyptic number.
It is an amenable number.
53000230023340 is an abundant number, since it is smaller than the sum of its proper divisors (58300253025716).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53000230023340 is a wasteful number, since it uses less digits than its factorization.
53000230023340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2650011501176 (or 2650011501174 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 25.
Adding to 53000230023340 its reverse (4332003200035), we get a palindrome (57332233223375).
The spelling of 53000230023340 in words is "fifty-three trillion, two hundred thirty million, twenty-three thousand, three hundred forty".
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