Base | Representation |
---|---|
bin | 11000000110100111101100… |
… | …11001110111110010111111 |
3 | 20221200010200000100120121102 |
4 | 30003103312121313302333 |
5 | 23421404223241104134 |
6 | 304421414310323315 |
7 | 14110262166535361 |
oct | 1403236631676277 |
9 | 227603600316542 |
10 | 53004030409919 |
11 | 15985979399456 |
12 | 5b4065265953b |
13 | 2376349261004 |
14 | d135a18ccd31 |
15 | 61db5313437e |
hex | 3034f6677cbf |
53004030409919 has 2 divisors, whose sum is σ = 53004030409920. Its totient is φ = 53004030409918.
The previous prime is 53004030409901. The next prime is 53004030410029. The reversal of 53004030409919 is 91990403040035.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53004030409919 is a prime.
It is a super-2 number, since 2×530040304099192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53004030409819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26502015204959 + 26502015204960.
It is an arithmetic number, because the mean of its divisors is an integer number (26502015204960).
Almost surely, 253004030409919 is an apocalyptic number.
53004030409919 is a deficient number, since it is larger than the sum of its proper divisors (1).
53004030409919 is an equidigital number, since it uses as much as digits as its factorization.
53004030409919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 47.
The spelling of 53004030409919 in words is "fifty-three trillion, four billion, thirty million, four hundred nine thousand, nine hundred nineteen".
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