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5302540552511 is a prime number
BaseRepresentation
bin100110100101001100000…
…0010111100100100111111
3200202220210011112121000202
41031022120002330210333
51143334100340140021
615135541542314115
71055044620012236
oct115123002744477
920686704477022
105302540552511
1117648819a5534
1271780212893b
132c6048350487
14144904093b1d
1592de7e6ba0b
hex4d2980bc93f

5302540552511 has 2 divisors, whose sum is σ = 5302540552512. Its totient is φ = 5302540552510.

The previous prime is 5302540552489. The next prime is 5302540552513. The reversal of 5302540552511 is 1152550452035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5302540552511 - 26 = 5302540552447 is a prime.

It is a super-4 number, since 4×53025405525114 (a number of 52 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 5302540552513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5302540552513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651270276255 + 2651270276256.

It is an arithmetic number, because the mean of its divisors is an integer number (2651270276256).

Almost surely, 25302540552511 is an apocalyptic number.

5302540552511 is a deficient number, since it is larger than the sum of its proper divisors (1).

5302540552511 is an equidigital number, since it uses as much as digits as its factorization.

5302540552511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150000, while the sum is 38.

The spelling of 5302540552511 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred fifty-two thousand, five hundred eleven".