Base | Representation |
---|---|
bin | 1111011011110011010… |
… | …11111100011100010111 |
3 | 1212200212002102100202002 |
4 | 13231321223330130113 |
5 | 32142100032242221 |
6 | 1043343220305515 |
7 | 53212613134064 |
oct | 7557153743427 |
9 | 1780762370662 |
10 | 530322540311 |
11 | 1949aa280873 |
12 | 86943b4229b |
13 | 3b0172a3415 |
14 | 1b94c42bc6b |
15 | dbdcc1e80b |
hex | 7b79afc717 |
530322540311 has 2 divisors, whose sum is σ = 530322540312. Its totient is φ = 530322540310.
The previous prime is 530322540287. The next prime is 530322540313. The reversal of 530322540311 is 113045223035.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530322540311 - 222 = 530318346007 is a prime.
Together with 530322540313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530322540313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265161270155 + 265161270156.
It is an arithmetic number, because the mean of its divisors is an integer number (265161270156).
Almost surely, 2530322540311 is an apocalyptic number.
530322540311 is a deficient number, since it is larger than the sum of its proper divisors (1).
530322540311 is an equidigital number, since it uses as much as digits as its factorization.
530322540311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 530322540311 its reverse (113045223035), we get a palindrome (643367763346).
The spelling of 530322540311 in words is "five hundred thirty billion, three hundred twenty-two million, five hundred forty thousand, three hundred eleven".
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