530333012033350 has 48 divisors (see below), whose sum is σ = 1028199974324688. Its totient is φ = 203319279757440.

The previous prime is 530333012033327. The next prime is 530333012033491. The reversal of 530333012033350 is 53330210333035.

It is a super-3 number, since 3×530333012033350³ (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2139178237 + ... + 2139426136.

It is an arithmetic number, because the mean of its divisors is an integer number (21420832798431).

Almost surely, 2^{530333012033350} is an apocalyptic number.

530333012033350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

530333012033350 is a deficient number, since it is larger than the sum of its proper divisors (497866962291338).

530333012033350 is a wasteful number, since it uses less digits than its factorization.

530333012033350 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4278604489 (or 4278604484 counting only the distinct ones).

The product of its (nonzero) digits is 109350, while the sum is 34.

Adding to 530333012033350 its reverse (53330210333035), we get a palindrome (583663222366385).

The spelling of 530333012033350 in words is "five hundred thirty trillion, three hundred thirty-three billion, twelve million, thirty-three thousand, three hundred fifty".