Base | Representation |
---|---|
bin | 100110100101101001101… |
… | …0010100110011111100100 |
3 | 200210000100102211222020212 |
4 | 1031023103102212133210 |
5 | 1143343114313341400 |
6 | 15140224330314552 |
7 | 1055111346354506 |
oct | 115132322463744 |
9 | 20700312758225 |
10 | 5303534512100 |
11 | 1765241a73040 |
12 | 717a3ab88a58 |
13 | 2c6176254146 |
14 | 14499a0abd76 |
15 | 92e55358335 |
hex | 4d2d34a67e4 |
5303534512100 has 144 divisors (see below), whose sum is σ = 12731304477696. Its totient is φ = 1901480832000.
The previous prime is 5303534512051. The next prime is 5303534512121. The reversal of 5303534512100 is 12154353035.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 272287562 + ... + 272307038.
Almost surely, 25303534512100 is an apocalyptic number.
5303534512100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5303534512100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6365652238848).
5303534512100 is an abundant number, since it is smaller than the sum of its proper divisors (7427769965596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5303534512100 is a wasteful number, since it uses less digits than its factorization.
5303534512100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22966 (or 22959 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 32.
Adding to 5303534512100 its reverse (12154353035), we get a palindrome (5315688865135).
The spelling of 5303534512100 in words is "five trillion, three hundred three billion, five hundred thirty-four million, five hundred twelve thousand, one hundred".
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