Base | Representation |
---|---|
bin | 1111011011110111001… |
… | …00011011000101101001 |
3 | 1212200221021211221012111 |
4 | 13231323210123011221 |
5 | 32142131123414423 |
6 | 1043350305242321 |
7 | 53213445444163 |
oct | 7557344330551 |
9 | 1780837757174 |
10 | 530354123113 |
11 | 194a16092461 |
12 | 869526333a1 |
13 | 3b0209b0979 |
14 | 1b9526cd933 |
15 | dbe08ac60d |
hex | 7b7b91b169 |
530354123113 has 8 divisors (see below), whose sum is σ = 546607416960. Its totient is φ = 514307877840.
The previous prime is 530354123077. The next prime is 530354123141. The reversal of 530354123113 is 311321453035.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530354123113 - 217 = 530353992041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530354123513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51756943 + ... + 51767188.
It is an arithmetic number, because the mean of its divisors is an integer number (68325927120).
Almost surely, 2530354123113 is an apocalyptic number.
It is an amenable number.
530354123113 is a deficient number, since it is larger than the sum of its proper divisors (16253293847).
530354123113 is a wasteful number, since it uses less digits than its factorization.
530354123113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103524287.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 530354123113 its reverse (311321453035), we get a palindrome (841675576148).
The spelling of 530354123113 in words is "five hundred thirty billion, three hundred fifty-four million, one hundred twenty-three thousand, one hundred thirteen".
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